Code Snippet [Bash]: Replace All Quotes In String

Here's a simple Bash script to replace all quotes with escaped quotes in a given string:

#!/bin/bash

# Function to replace quotes with escaped quotes in a string
escape_quotes() {
    local input_string="$1"
    local escaped_string=$(echo "$input_string" | sed 's/"/\\"/g')
    echo "$escaped_string"
}

# Example usage
input_string='This is a "test" string with "quotes".'
escaped_string=$(escape_quotes "$input_string")

echo "Original string: $input_string"
echo "Escaped string: $escaped_string"

This script defines a function escape_quotes that takes an input string and uses sed to replace all double quotes (") with escaped quotes (\"). It then prints the original and escaped strings. You can modify the input_string variable to test with different strings.

Save this script to a file, for example, escape_quotes.sh, and make it executable with the command chmod +x escape_quotes.sh. Then you can run it with ./escape_quotes.sh.